51^2=24^2+x^2

Solution for 51^2=24^2+x^2 equation:

51^2=24^2+x^2

We move all terms to the left:

51^2-(24^2+x^2)=0

We add all the numbers together, and all the variables

-(24^2+x^2)+2601=0

We get rid of parentheses

-x^2+2601-24^2=0

We add all the numbers together, and all the variables

-1x^2+2025=0

a = -1; b = 0; c = +2025;
Δ = b2-4ac
Δ = 02-4·(-1)·2025
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*-1}=\frac{-90}{-2}
=+45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*-1}=\frac{90}{-2}
=-45
$